site stats

In fig. 9.3 if ∠aob 125° then ∠cod is equal t

WebIn Fig. 9.3, if ∠AOB=1250,then ∠COD is equal to A 62.50 B 450 C 350 D 550 Answer Correct option is D 550 Given−AB,BC,CD&ADaretangentsdrawnfromthepointsA,B,CtothecirclewithcentreO. OA,OB,OC&ODarethelinesjoiningOwithA,B,C&Drespectively.∠AOB=125oTofindout−∠DOC=? … WebFeb 3, 2024 · In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. - Sarthaks eConnect Largest Online Education Community In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. ← Prev Question Next Question → 0 votes 18.2k views

In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to - Cuemath

WebIf two triangles have the same base and also have equal areas, then these triangles must lie between the same parallels. Let us construct DN ⊥ AC and BM ⊥ AC. i) In ∆DON and ∆BOM, ∠DNO = ∠BMO = 90° (By construction) ∠DON = ∠BOM (Vertically opposite angles are equal) OD = OB (Given) By AAS congruence rule, ΔDON ≅ ΔBOM DN = BM (By CPCT) ... (1) WebMay 16, 2024 · In figure, chords AB and CD of circle with center O, arc same. If ∠AOB = 55°, then ∠COD will be : (A) 110° (B) 75° (C) 90° (D) 55° circle class-10 1 Answer +1 vote answered May 16, 2024 by VinodeYadav (35.7k points) selected May 17, 2024 by HarshKumar Best answer Answer is (D) 55° Chord AB = Chord CD ˆAB A B ^ = ˆC D C D ^ … motels in newcomerstown ohio https://davemaller.com

In Fig. chords AD and BC intersect each other at right ... - Sarthaks

WebNov 17, 2014 · EXPERTS, PLEASE ANSWER THIS AS SOON AS POSSIBLE If APB and CQD are two parallel lines then find the type of quadrilateral formed by the bisectors of the … WebIn figure, if ∠AOB = 125°, then ∠COD is equal to (a) 62.5° (b) 45° (c) 35° (d) 55° Solution: (d) We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. Question 3: In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. WebApr 27, 2024 · In figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: (D) We know that the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. ⇒ ∠AOB + ∠COD = 180° ⇒ ∠COD = 180° – ∠AOB = 180° – 125° = 55° Question 3 mining work clothes

In Fig., if AB DE and BD FG such that ∠FGH = 125° and ∠B = 55 ...

Category:In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to

Tags:In fig. 9.3 if ∠aob 125° then ∠cod is equal t

In fig. 9.3 if ∠aob 125° then ∠cod is equal t

In Fig.8.7, the quadrilateral ABCD circumscribes a circle ... - Sarthaks

WebAug 28, 2024 · Best answer (D) 55° ABCD is a quadrilateral circumscribing the circle We know that, the opposite sides of a quadrilateral circumscribing a circle subtend … WebIn Fig. 9.3, if AOB = 125°, then COD is equal to CBSE Circles Class 10 Exercise 9.1 Maths NCERT Exemplar In Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° …

In fig. 9.3 if ∠aob 125° then ∠cod is equal t

Did you know?

WebIn figure, if ∠AOB = 125°, then ∠COD is equal to As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle. So, we have ∠AOB + ∠COD = 180° 125° + ∠COD = 180° ∠COD = 55° Prev Q1 1 .. 10 Q3 Next WebAug 24, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° - Sarthaks eConnect Largest Online Education Community.

WebJan 24, 2024 · closed Mar 15, 2024 by faiz In the given figure, arc AB = arc CD and if ∠AOB = 40°, then ∠COD = A) 80° B) 40° C) 140° D) 90° circles class-9 Share It On 2 Answers +1 vote answered Mar 12, 2024 by VishalDhakar (56.9k points) selected Mar 15, 2024 by faiz Best answer Correct option is (B) 40° ∵ ∵ arc AB ≅ ≅ arc CD WebDec 14, 2024 · In the given figure, if ∠AOB=125∘, then ∠COD is equal to: (A) 62.5∘ (B) 45∘ (C) 35∘ (D) 55∘ ... After some time, the angle of elevation reduces to 3 0 ∘ (see Fig. 9.13). Find the distance travelled by the balloon during the interval. 15. …

WebOct 28, 2024 · Here is your answer: The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center. ABCD will meet at a point where it won't … WebIn the given figure, if ∠AOB = 125°, then ∠COD is equal to (a) 62.5° (b) 45° (c) 35° (d) 55° For Short Notes, Revision Notes And NCERT Solution. Visit Us at- …

WebApr 20, 2024 · ∠FGH + ∠FGE = 180° (Linear pair) 125° + y = 180° y = 55° ∠ABC = ∠BDE (Alternate angles) ∠BDF = ∠EFG = 55° (Alternate angles) ∠EFG + ∠FEG = 125° (By exterior angle theorem) 55° + ∠FEG = 125° ∠FEG = x = 70° Thus, x = 70° and y = 55° ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET Mock Test

WebIn figure, if ∠AOB=125∘. Then ∠ COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution We know that, the opposite sides of a quadrilateral circumscribing a circle subtend … mining workers unionWebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5° b. 45° c. 35° d. 55° Solution: Given, ∠AOB = 125° We have to find the measure of angle COD. motels in newbury park californiaWebAnswer: Let O be the centre of two concentric circles C 1 and C 2 , whose radii are r 1 = 4 cm and r 2 = 5 cm. Now, we draw a chord AC of circle C 2 which is tangent to circle C 1 at B. Also, join OB, which is perpendicular to AC. So ∆ OBC is a right-angled triangle ∴ (OB) 2 + (BC) 2 = (OC) 2 (Pythagoras theorem) (4) 2 + (BC) 2 = (5) 2 motels in newcastle deWebIn Fig. 9.25, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that: i) ar (DOC) = ar (AOB) ii) ar (DCB) = ar (ACB) iii) DA CB. Learn … motels in new iberia laWebIn figure, if ∠AOB = 125°, then ∠COD is equal to 55°. Explanation: As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a … motels in new hampshireWebIn figure, if ∠ AOB = 125°, then ∠ COD is equal to. 3. In figure, AB is a chord of the circle and AOC is its diameter such that ∠ ACB = 50°. If AT is the tangent to the circle at the point A, then ∠ BAT is equal to. 4. mining work hsn codeWebJan 9, 2024 · In Fig., O is the centre of the circle. If ∠APB∠APB= 50°, find ∠AOB and ∠OAB. Solution: ∠APB=50° By degree measure theorem ∠AOB=2APB ∠APB=2*50°=100° since OA=OB [Radius of circle] Then ∠OAB=∠OBA [Angles opposite to equal sides] Let ∠OAB=x In OAb, by angle sum property ∠OAB+∠OBA+∠AOB=180° x+x+100°=180° 2x=180°-100° … mining working face