WebIn Fig. 9.3, if ∠AOB=1250,then ∠COD is equal to A 62.50 B 450 C 350 D 550 Answer Correct option is D 550 Given−AB,BC,CD&ADaretangentsdrawnfromthepointsA,B,CtothecirclewithcentreO. OA,OB,OC&ODarethelinesjoiningOwithA,B,C&Drespectively.∠AOB=125oTofindout−∠DOC=? … WebFeb 3, 2024 · In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. - Sarthaks eConnect Largest Online Education Community In Fig.8.7, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB =115degree, then find ∠COD. ← Prev Question Next Question → 0 votes 18.2k views
In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to - Cuemath
WebIf two triangles have the same base and also have equal areas, then these triangles must lie between the same parallels. Let us construct DN ⊥ AC and BM ⊥ AC. i) In ∆DON and ∆BOM, ∠DNO = ∠BMO = 90° (By construction) ∠DON = ∠BOM (Vertically opposite angles are equal) OD = OB (Given) By AAS congruence rule, ΔDON ≅ ΔBOM DN = BM (By CPCT) ... (1) WebMay 16, 2024 · In figure, chords AB and CD of circle with center O, arc same. If ∠AOB = 55°, then ∠COD will be : (A) 110° (B) 75° (C) 90° (D) 55° circle class-10 1 Answer +1 vote answered May 16, 2024 by VinodeYadav (35.7k points) selected May 17, 2024 by HarshKumar Best answer Answer is (D) 55° Chord AB = Chord CD ˆAB A B ^ = ˆC D C D ^ … motels in newcomerstown ohio
In Fig. chords AD and BC intersect each other at right ... - Sarthaks
WebNov 17, 2014 · EXPERTS, PLEASE ANSWER THIS AS SOON AS POSSIBLE If APB and CQD are two parallel lines then find the type of quadrilateral formed by the bisectors of the … WebIn figure, if ∠AOB = 125°, then ∠COD is equal to (a) 62.5° (b) 45° (c) 35° (d) 55° Solution: (d) We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. Question 3: In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. WebApr 27, 2024 · In figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution: (D) We know that the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. ⇒ ∠AOB + ∠COD = 180° ⇒ ∠COD = 180° – ∠AOB = 180° – 125° = 55° Question 3 mining work clothes