WebIf its 10th term is 41, then find the sum of its first fifteen terms. Solution: Question 33. The 13th term of an AP is four times its 3rd term. If its fifth term is 16, then find the sum of its first ten terms. Solution: Question 34. In an A.P., if the 12th term is -13 and the sum of its first four terms is 24, find the sum of its first ten terms. WebYou would do the exact same process, but you would have to SOLVE for "n" (number of terms) first. To do so, you must start with the arithmetic sequence formula: tn = a + d(n −1) Then, sub in all known values. tn = 15 (last term of the sequence), a = 1 (first term), d = 2 (difference between terms) and solve for n like so: 15 = 1 + 2(n −1)
Finding first term and common difference when sum is …
WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same? WebExpert Answers. hala718. Certified Educator. Share Cite. Le a1, a2, ..., a10 are terms of an A.P. given S10 = a1+a2+...+10 = 150. But we know that: s10 = (a1+a10)*10/2 = 150. ==> … british columbia game designer
Sum of n Natural Numbers: Formula, Derivation & Solved …
WebOct 20, 2024 · Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. ⇒ -150= 10/2 [ 2a + 9d ] ⇒ … WebSolution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. For … WebGiven that sum of the first 10 terms of an A.P. is -150. S 10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 … british columbia fly fishing